m^2+13m=42

Solution for m^2+13m=42 equation:

m^2+13m=42

We move all terms to the left:

m^2+13m-(42)=0

a = 1; b = 13; c = -42;
Δ = b2-4ac
Δ = 132-4·1·(-42)
Δ = 337
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-\sqrt{337}}{2*1}=\frac{-13-\sqrt{337}}{2}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+\sqrt{337}}{2*1}=\frac{-13+\sqrt{337}}{2}
$